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Unit of momentum

If you have played cricket, you would have experienced that catching a ball which is moving with a higher velocity is more difficult than catching a ball which is moving with lesser velocity. Similarly, it is easier to catch a table tennis ball as compared to a cricket ball when both are dropped from the same height. Thus, we see that moving bodies postess a physical quantity associated with their motion which determine how much force is required to bring them to rest . This quantity which depends on the mass and velocity of the moving body is called momentum and is defined as momentum (p) = mass (m) × velocity (v) So momentum (p) = mass(m) × velocity (v) = kg × m s-1 SI unit of momentum is kg m s-1 or Newton,  Cgs unit of momentum is g cm s-1   Law of conservation of momentum   The total momentum of a system of bodies remains constant unless there is a net external force acting on the system.

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The magnitudes of power of a biconvex lens (refractive index 1.5) and a plano-concave lens (refractive index 1.7) are equal. If the curvature of the concave surface of the plano-concave lens exactly matches the curvature of the back surface of the biconvex lens, find the ratio of radii of curvature of the front and back surfaces of the biconvex lens

Options: A) 5 : 2 B) 5 : 12 C) 12 : 5 D) 2 : 5 Solution Lens maker formula: 1/f = (μ − 1) (1/R₁ − 1/R₂) For biconvex lens: μ₁ = 1.5 Pb = (1.5 − 1)(1/R₁ − 1/R₂) Pb = 0.5 (1/R₁ − 1/R₂) For plano-concave lens: μ₂ = 1.7 Pp = (1.7 − 1)(1/R) Pp = 0.7 (1/R) Since magnitudes are equal: 0.5 (1/R₁ − 1/R₂) = 0.7 (1/R₂) Solve: 0.5/R₁ − 0.5/R₂ = 0.7/R₂ 0.5/R₁ = 1.2/R₂ R₁ / R₂ = 5 / 2 Correct Answer: A