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IAT Mock Test 2026 – Part 1

Marking Scheme: +4 Correct | -1 Incorrect | 0 Unattempted

Q1. A particle moves in a straight line such that its displacement is given by x = t³ − 6t² + 9t + 4. At what time is its velocity zero?

(A) 1 s

(B) 2 s

(C) 3 s

(D) Both A and C

Correct Answer: (D)

v = dx/dt = 3t² − 12t + 9 = 3(t−1)(t−3). Therefore velocity is zero at t = 1 s and 3 s.

Q2. The number of stereoisomers possible for a compound with two chiral centers is:

(A) 2

(B) 4

(C) 6

(D) 8

Correct Answer: (B)

Maximum stereoisomers = 2ⁿ, where n = number of chiral centers. Hence 2² = 4.

Q3. If z = 1 + i√3, then the principal argument of z is:

(A) π/6

(B) π/3

(C) π/2

(D) 2π/3

Correct Answer: (B)

tan θ = √3/1 = √3, first quadrant ⇒ θ = π/3.

Q4. A wire of resistance R is stretched to double its original length. The new resistance becomes:

(A) R/2

(B) R

(C) 2R

(D) 4R

Correct Answer: (D)

On stretching to double length, area becomes half. R ∝ L/A ⇒ R' = (2L)/(A/2) = 4R.

Q5. Which species has maximum bond angle?

(A) NH₃

(B) H₂O

(C) CH₄

(D) BF₃

Correct Answer: (D)

BF₃ is trigonal planar with 120° bond angle, maximum among given options.

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Two wires A and B have: Length A = 6.0 cm Length B = 5.4 cm Area A = 3.0 × 10⁻⁵ m² Area B = 4.5 × 10⁻⁵ m² Both are stretched by same force producing same extension. If ratio of Young’s modulus is A:B = x : 3, find x

Options: A) 1 B) 4 C) 2 D) 5 Solution Using: Y = (F L) / (A ΔL) Since F and ΔL same: YA / YB = (LA AB) / (LB AA) Substitute: = (6.0 × 4.5) / (5.4 × 3.0) = 27 / 16.2 = 5 / 3 So, x = 5 Correct Answer: D