IAT Mock Test 2026 – Part 1
Marking Scheme: +4 Correct | -1 Incorrect | 0 Unattempted
Q1. A particle moves in a straight line such that its displacement is given by x = t³ − 6t² + 9t + 4. At what time is its velocity zero?
(A) 1 s
(B) 2 s
(C) 3 s
(D) Both A and C
Correct Answer: (D)
v = dx/dt = 3t² − 12t + 9 = 3(t−1)(t−3). Therefore velocity is zero at t = 1 s and 3 s.
v = dx/dt = 3t² − 12t + 9 = 3(t−1)(t−3). Therefore velocity is zero at t = 1 s and 3 s.
Q2. The number of stereoisomers possible for a compound with two chiral centers is:
(A) 2
(B) 4
(C) 6
(D) 8
Correct Answer: (B)
Maximum stereoisomers = 2ⁿ, where n = number of chiral centers. Hence 2² = 4.
Maximum stereoisomers = 2ⁿ, where n = number of chiral centers. Hence 2² = 4.
Q3. If z = 1 + i√3, then the principal argument of z is:
(A) π/6
(B) π/3
(C) π/2
(D) 2π/3
Correct Answer: (B)
tan θ = √3/1 = √3, first quadrant ⇒ θ = π/3.
tan θ = √3/1 = √3, first quadrant ⇒ θ = π/3.
Q4. A wire of resistance R is stretched to double its original length. The new resistance becomes:
(A) R/2
(B) R
(C) 2R
(D) 4R
Correct Answer: (D)
On stretching to double length, area becomes half. R ∝ L/A ⇒ R' = (2L)/(A/2) = 4R.
On stretching to double length, area becomes half. R ∝ L/A ⇒ R' = (2L)/(A/2) = 4R.
Q5. Which species has maximum bond angle?
(A) NH₃
(B) H₂O
(C) CH₄
(D) BF₃
Correct Answer: (D)
BF₃ is trigonal planar with 120° bond angle, maximum among given options.
BF₃ is trigonal planar with 120° bond angle, maximum among given options.
No comments:
Post a Comment