Skip to main content

Moment of force

When a force is applied on a door handle, it tends to turn (open or close) the door about the hinges. This rotating or turning effect of a force about a fixed point or fixed axis is called moment of force about that point. This moment of force, i.e., the turning effect is maximum if the applied force is perpendicular to the plane of the door and the point of application is the farthest from the hinges. Therefore, the moment of force is measured by the product of the magnitude of the force and the perpendicular distance between the fixed point or the fixed axis and the line of action of the force. The moment of force, also called torque, is a vector quantity and is given as a cross product of the force vector,\(\vec{F}\)and the radius vector, \(\vec{r}\) as, \(\vec{τ}\) = \(\vec{r}\) ×\(\vec{F}\) and the magnitude of moment of force (torque) is given by τ = rF sinθ = F. d Here, this τ represent moment of force (torque), also called (tau). Note - if the perpendicular distance between the line of action of the applied force and the fixed point is greater, greater will be the training effect. Example : Door handles are provided far away from the hinges so that less amount of force is required to obtain greater turning effect.
Questionfind the moment of force if a force 8 N is applied on a door, perpendicular to its plane at distance of 100 cm from its hinge. Solution Given: Force is 8 N Perpendicular distance,  d = 100cm = 1m Moment of force = F×d Thus, moment of force = 2 × 1                                           = 2N

Concept of Zero Moment of force

If the line of action of a force passes through the axis of rotation, its perpendicular distance from the axis is zero. Therefore, its moment about that axis is also zero, In simple way - Turning effect is zero when forces are applied on the fixed point or on the fixed axis.

Unit of Moment of Force

Moment of force = Force × perpendicular distance Hence, unit of torque = N (unit of force) × m (unit of distance) Thus, the SI unit of moment of force is N m, CGS unit of moment of force is dyne cm.

Dimension formula of moment of force

Moment of force = Force × perpendicular distance Thus, [torque] = [Force] [distance] = [M1 L1 T -2] × [L] = [M1 L2 T-2 ]

Principal of moment

When a number of parallel forces act on a rigid body and the body is in equilibrium, then the algebraic sum of the moments of the individual forces about any point is equal to zero, i.e., sum of anti-clockwise moments is equal to sum of clockwise moments.

Comments

Popular posts from this blog

IAT 2025 Question Paper

IAT 2025 Question Paper Marking Scheme: +4 Correct | -1 Incorrect | 0 Unattempted Q1. (Physics) A ball is projected vertically upward with speed 30 m/s. Neglect air resistance. The time taken to return to the point of projection is: (A) 3 s (B) 4 s (C) 5 s (D) 6 s Show Answer Answer: (D) Total time = 2u/g = 2×30/10 = 6 s. Q2. (Chemistry) Which species has the maximum number of unpaired electrons? (A) Fe²⁺ (B) Fe³⁺ (C) Mn²⁺ (D) Cu²⁺ Show Answer Answer: (C) Mn²⁺ = 3d⁵ configuration → maximum unpaired electrons. Q3. (Mathematics) If sin θ = 3/5 and θ lies in first quadrant, then cos θ is: (A) 4/5 (B) 3/4 (C) 5/4 (D) 2/5 Show Answer Answer: (A) cos²θ = 1 − sin²θ = 1 − 9/25 = 16/25 ⇒ cos θ = 4/5. Q4. (Biology) The functional unit of kidney is: (A) Neuron (B) Alveoli (C) Nephron (D) Glomerulus Show Answer Answer: (C) Nephron is the structural and functional unit of kidney. Q5. (Physics) Escape velocity from Earth is approximately: (A) 7.9 km/s (B) 9.8 km/...
IAT Mock Test 2026 – Part 1 Marking Scheme: +4 Correct | -1 Incorrect | 0 Unattempted Q1. A particle moves in a straight line such that its displacement is given by x = t³ − 6t² + 9t + 4. At what time is its velocity zero? (A) 1 s (B) 2 s (C) 3 s (D) Both A and C Show Answer Correct Answer: (D) v = dx/dt = 3t² − 12t + 9 = 3(t−1)(t−3). Therefore velocity is zero at t = 1 s and 3 s. Q2. The number of stereoisomers possible for a compound with two chiral centers is: (A) 2 (B) 4 (C) 6 (D) 8 Show Answer Correct Answer: (B) Maximum stereoisomers = 2ⁿ, where n = number of chiral centers. Hence 2² = 4. Q3. If z = 1 + i√3, then the principal argument of z is: (A) π/6 (B) π/3 (C) π/2 (D) 2π/3 Show Answer Correct Answer: (B) tan θ = √3/1 = √3, first quadrant ⇒ θ = π/3. Q4. A wire of resistance R is stretched to double its original length. The new resistance becomes: (A) R/2 (B) R (C) 2R (D) 4R Show Answer Correct Answer: (D) On stretching to double length, area...

The magnitudes of power of a biconvex lens (refractive index 1.5) and a plano-concave lens (refractive index 1.7) are equal. If the curvature of the concave surface of the plano-concave lens exactly matches the curvature of the back surface of the biconvex lens, find the ratio of radii of curvature of the front and back surfaces of the biconvex lens

Options: A) 5 : 2 B) 5 : 12 C) 12 : 5 D) 2 : 5 Solution Lens maker formula: 1/f = (μ − 1) (1/R₁ − 1/R₂) For biconvex lens: μ₁ = 1.5 Pb = (1.5 − 1)(1/R₁ − 1/R₂) Pb = 0.5 (1/R₁ − 1/R₂) For plano-concave lens: μ₂ = 1.7 Pp = (1.7 − 1)(1/R) Pp = 0.7 (1/R) Since magnitudes are equal: 0.5 (1/R₁ − 1/R₂) = 0.7 (1/R₂) Solve: 0.5/R₁ − 0.5/R₂ = 0.7/R₂ 0.5/R₁ = 1.2/R₂ R₁ / R₂ = 5 / 2 Correct Answer: A