Skip to main content

Simple Pendulum

A point connected to a light mass is called a simple pendulum suspended with mass and fixed support.

Simple pendulum experiment

A simple pendulum consists of a particle of mass ‘m’ usually called bob, suspended from a rigid support with the help of an unstretchable, mass less string. A practical simple pendulum has a small metallic bob suspended from an unstretchable thread and its length l ‘is the distance between the point of suspension and the center of gravity of the bob.

When a simple pendulum is set to oscillate it moves to and fro about it’s mean position between the two extremes A and B with constant amplitude as shown in the figure.

 

showing position the mean and extreme position of a simple pendulum
Figure 2 showing position the mean and extreme position of a simple pendulum

When we plot  the horizontal displacement and the time on a graph paper the curve obtained would be in the form of a wave.

Displacement Vs Timeline of a simple pendulum
Figure 3 Displacement Vs Timeline of a simple pendulum 

 

Each loop of the graph represents one complete oscillation of the pendulum. When the bob is at its mean position the displacement is zero and at its extremes the displacement is either +a or -a ‘referring to the amplitude of the oscillation.

Low of semple pendulum

A freely oscillating simple pendulum of a given length always possesses a constant time period and thus it can be used as a time measuring device. Galileo discovered the laws of simple pendulum.

1st Law of Simple Pendulum

For small values ​​of amplitude the time period of a simple pendulum of a given length is independent of the amplitude of oscillation.

2nd Law of Simple Pendulum

For small values ​​of amplitude the period of a simple pendulum of a given length is independent of its mass, size, density and shape of the bob.

Verification of lows of simple pendulum 

Verification of 1 low
arrangement to show that time period of a simple pendulum is independent of its amplitude

suspend a simple pendulum of length 100 cm from the cork fixed to a retort stand as shown in the figure. Set the simple pendulum to oscillate uniformly about its mean position with a small amplitude, say, 8 cm. Tabulate the time taken by the bob for 20 oscillations in two trials by using a stop watch. Repeat the same procedure by changing the amplitude in two steps say 6 cm and 4 cm. Determine the time period in each case. Determine the average time period of pendulum in each case.

Related post

Thrust

What is force

Units of momentum

Comments

Popular posts from this blog

IAT 2025 Question Paper

IAT 2025 Question Paper Marking Scheme: +4 Correct | -1 Incorrect | 0 Unattempted Q1. (Physics) A ball is projected vertically upward with speed 30 m/s. Neglect air resistance. The time taken to return to the point of projection is: (A) 3 s (B) 4 s (C) 5 s (D) 6 s Show Answer Answer: (D) Total time = 2u/g = 2×30/10 = 6 s. Q2. (Chemistry) Which species has the maximum number of unpaired electrons? (A) Fe²⁺ (B) Fe³⁺ (C) Mn²⁺ (D) Cu²⁺ Show Answer Answer: (C) Mn²⁺ = 3d⁵ configuration → maximum unpaired electrons. Q3. (Mathematics) If sin θ = 3/5 and θ lies in first quadrant, then cos θ is: (A) 4/5 (B) 3/4 (C) 5/4 (D) 2/5 Show Answer Answer: (A) cos²θ = 1 − sin²θ = 1 − 9/25 = 16/25 ⇒ cos θ = 4/5. Q4. (Biology) The functional unit of kidney is: (A) Neuron (B) Alveoli (C) Nephron (D) Glomerulus Show Answer Answer: (C) Nephron is the structural and functional unit of kidney. Q5. (Physics) Escape velocity from Earth is approximately: (A) 7.9 km/s (B) 9.8 km/...
IAT Mock Test 2026 – Part 1 Marking Scheme: +4 Correct | -1 Incorrect | 0 Unattempted Q1. A particle moves in a straight line such that its displacement is given by x = t³ − 6t² + 9t + 4. At what time is its velocity zero? (A) 1 s (B) 2 s (C) 3 s (D) Both A and C Show Answer Correct Answer: (D) v = dx/dt = 3t² − 12t + 9 = 3(t−1)(t−3). Therefore velocity is zero at t = 1 s and 3 s. Q2. The number of stereoisomers possible for a compound with two chiral centers is: (A) 2 (B) 4 (C) 6 (D) 8 Show Answer Correct Answer: (B) Maximum stereoisomers = 2ⁿ, where n = number of chiral centers. Hence 2² = 4. Q3. If z = 1 + i√3, then the principal argument of z is: (A) π/6 (B) π/3 (C) π/2 (D) 2π/3 Show Answer Correct Answer: (B) tan θ = √3/1 = √3, first quadrant ⇒ θ = π/3. Q4. A wire of resistance R is stretched to double its original length. The new resistance becomes: (A) R/2 (B) R (C) 2R (D) 4R Show Answer Correct Answer: (D) On stretching to double length, area...

The magnitudes of power of a biconvex lens (refractive index 1.5) and a plano-concave lens (refractive index 1.7) are equal. If the curvature of the concave surface of the plano-concave lens exactly matches the curvature of the back surface of the biconvex lens, find the ratio of radii of curvature of the front and back surfaces of the biconvex lens

Options: A) 5 : 2 B) 5 : 12 C) 12 : 5 D) 2 : 5 Solution Lens maker formula: 1/f = (μ − 1) (1/R₁ − 1/R₂) For biconvex lens: μ₁ = 1.5 Pb = (1.5 − 1)(1/R₁ − 1/R₂) Pb = 0.5 (1/R₁ − 1/R₂) For plano-concave lens: μ₂ = 1.7 Pp = (1.7 − 1)(1/R) Pp = 0.7 (1/R) Since magnitudes are equal: 0.5 (1/R₁ − 1/R₂) = 0.7 (1/R₂) Solve: 0.5/R₁ − 0.5/R₂ = 0.7/R₂ 0.5/R₁ = 1.2/R₂ R₁ / R₂ = 5 / 2 Correct Answer: A